Match List -I with List -II

| vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$ F=\eta A \frac{d v}{d y} $
$ {\left[M L T^{-2}\right]=\eta\left[L^2\right]\left[T^{-1}\right]} $
$ \eta=\left[M L^{-1} T^{-1}\right] $
$ S . T=\f

Vedclass · Accepted Answer

$ A-III, B-IV, C-II, D-I$

Vedclass · Answer

$ F=\eta A \frac{d v}{d y} $
$ {\left[M L T^{-2}\right]=\eta\left[L^2\right]\left[T^{-1}\right]} $
$ \eta=\left[M L^{-1} T^{-1}\right] $
$ S . T=\frac{F}{\ell}=\frac{\left[M L T^{-2}\right]}{[L]}=\left[M L^0 T^{-2}\right] $
$ L=m v r=\left[M L^2 T^{-1}\right] $
$ K . E=\frac{1}{2} I \omega^2=\left[M L^2 T^{-2}\right]$

	List $-I$		List $-II$
$A$.	Coefficient of Viscosity	$I$.	$[M L^2T^{–2}]$
$B$.	Surface Tension	$II$.	$[M L^2T^{–1}]$
$C$.	Angular momentum	$III$.	$[M L^{-1}T^{–1}]$
$D$.	Rotational Kinetic energy	$IV$.	$[M L^0T^{–2}]$

Match List $-I$ with List $-II$

List $-I$ List $-II$

$A$. Coefficient of Viscosity $I$. $[M L^2T^{–2}]$

$B$. Surface Tension $II$. $[M L^2T^{–1}]$

$C$. Angular momentum $III$. $[M L^{-1}T^{–1}]$

$D$. Rotational Kinetic energy $IV$. $[M L^0T^{–2}]$

Similar Questions

The dimension of $\frac{1}{{\sqrt {{\varepsilon _0}{\mu _0}} }}$ is that of

Which of the following is a dimensional constant?

The dimensions of shear modulus are

The dimension of the ratio of angular to linear momentum is

The physical quantity that has no dimensions

Match List $-I$ with List $-II$ List $-I$ List $-II$ $A$. Coefficient of Viscosity $I$. $[M L^2T^{–2}]$ $B$. Surface Tension $II$. $[M L^2T^{–1}]$ $C$. Angular momentum $III$. $[M L^{-1}T^{–1}]$ $D$. Rotational Kinetic energy $IV$. $[M L^0T^{–2}]$